(D^3+D)y=2x^2+4sinx

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Solution for (D^3+D)y=2x^2+4sinx equation: 


Simplifying
(D3 + D) * y = 2x2 + 4sinx

Reorder the terms:
(D + D3) * y = 2x2 + 4sinx

Reorder the terms for easier multiplication:
y(D + D3) = 2x2 + 4sinx
(D * y + D3 * y) = 2x2 + 4sinx
(yD + yD3) = 2x2 + 4sinx

Reorder the terms:
yD + yD3 = 4insx + 2x2

Solving
yD + yD3 = 4insx + 2x2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Reorder the terms:
-4insx + -2x2 + yD + yD3 = 4insx + 2x2 + -4insx + -2x2

Reorder the terms:
-4insx + -2x2 + yD + yD3 = 4insx + -4insx + 2x2 + -2x2

Combine like terms: 4insx + -4insx = 0
-4insx + -2x2 + yD + yD3 = 0 + 2x2 + -2x2
-4insx + -2x2 + yD + yD3 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-4insx + -2x2 + yD + yD3 = 0

The solution to this equation could not be determined.

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